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where the xt are points of E, and r > 0. Suppose that H satisfies the condition
( Choose e > 0 such that 2sc < %r. For each index /', there exists an
an(i) such that xt - an(i) e eV. By virtue of (, it follows that for each
x' e H we have

|<X- - an(i) ,x'-x'0y\ 2&c < ir,

and the relations |<flrt(0' x'  x'0y\ < %r therefore imply the inequalities
( Since the weak topology is Hausdorff, we have shown that H is
metrizable (12.4.6). More precisely, the above argument shows that the map-
ping ;K'!-#, -x'>)no f H into the product space KN (where K = R or C)
is a homeomorphism of H onto a subspace L of KN. So it remains to be shown
that L is compact.

In the first place, the projections of L are boundedsubsets of K (and there-
fore relatively compact ((3.17.6) and (3.20.16))): for each index n there exists
ln > 0 such that lnan e V and therefore |<aw, x'>| ^ c/ln for all xf e H. By
virtue of (12.5.9), (12.5.4), and (3.17.3), it remains to be shown that L is
closed in KN. Now if (x'm) is a sequence of points in H such that for each n the
sequence an, x'my)m^ converges in K, then it follows from (7.5.5) that the
sequence (x'm) converges simply in V. Since for each z e E there exists a
scalar y such that yz e V (so that <z, *4> = y"1^, x'my)9 the sequence (x'm)
converges simply in E: its limit yr is a linear mapping, by the principle of
extension of identities, and is continuous by (7.5.5), and is therefore a point
of H.                                                                                             Q.E.D.

We recall that if E is a normed space, its dual E' = <&(E; K) is a
Banach space with respect to the norm \\x'\\ = sup |<x, x'y\ (5.7.3); since

KJC, xry\ ^ \\x\\ - \\x'\\> the topology defined by this norm (sometimes called
the strong topology on E') is finer than the weak topology on E'.

(12.15.8)   Let E be a normed space. The mapping x'\~* \\x'\\ ofE' into R is
lower semicontinuous with respect to the weak topology.

For it is the upper envelope of the weakly continuous mappings
x'*-!<#, x'y\, where x runs through the ball \\x\\ ^ 1 in E. Hence the result
follows from (12.7.7).

c) is a sequence in E' which converges weakly to a', then by (12.7.13)
we have

(          'fa + u2) = \ + * u2 ,        \Xu) =A'*u